Hi Quickbase Community Developers,
I have created a new form on the table. This means that the table now has two forms - the original / default one which I always land on when I invoke the application and the additional one which I just created. All the fields in the new form are also on the default form however the new form has fewer fields than the default form. In the default form I have also created a button that I would like to invoke the new form with when it?s clicked. Do you guys know how can I code the button on the default form to invoke / display the new form when it?s clicked. Kindly advise.