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Display today's date in ""F d, Y"" (PHP date format)

  • 1.  Display today's date in ""F d, Y"" (PHP date format)

    Posted 03-05-2019 17:57
    I'm sure there is a simple way to do this, but I am struggling.

    I know you have the Date() function but that only accepts text.

    I've tried Date( Year( Today() ), Month( Today() ), Day( Today() ) ) but that doesn't work because the Year, Month, Day parts are date numbers. 

    I've tried using various formulas including ToFormattedText, ToText.

    Also, tried using AdjustYear([Date], 0)  but the output is actually mm-dd-yyyy not as indicated in formula reference ( "AdjustYear(ToDate("2/20/99"), 2) returns February 20, 2001" ) on https://login.quickbase.com/db/6ewwzuuj?a=dr&rid=35&rl=4m">https://login.quickbase.com/db/6ewwzuuj?a=dr&rid=35&rl=4m">https://login.quickbase.com/db/6ewwzuuj?a=dr&rid=35&rl=4m.

    NOTE: PHP Date format "F d, Y" would yield March 5, 2019


  • 2.  RE: Display today's date in ""F d, Y"" (PHP date format)

    Posted 03-05-2019 18:00
    Is this what you want?

    var date MyDate = (insert your date field here);

    List("-",
    Case(Month($MyDate),
    1,"Jan",
    2,"Feb",
    3,"Mar",
    4,"Apr",
    5,"May",
    6,"Jun",
    7,"Jul",
    8,"Aug",
    9,"Sep",
    10,"Oct",
    11,"Nov",
    12,"Dec"),
    Right("0" & ToText(Day($MyDate)),2),
    ToText(Year($MyDate)))


  • 3.  RE: Display today's date in ""F d, Y"" (PHP date format)

    Posted 03-05-2019 18:31
    Kind of works, but it Needs to be "March 5, 2019" not "March-05-2019" so the list part with "-" doesn't work.

    Thanks for the reply... seems overly complicated for as many times as I need to use it. But will probably just load a date .js function so I can use it repeatedly.