ContributionsMost RecentMost LikesSolutionsRe: Need help on a syntax error So by removing the quotations around the numeric results it worked! Thank you for your help! Re: Need help on a syntax errorYes, it is a formula - numeric field type.Re: Need help on a syntax error If( Year(Today())-Year([Hire Date]) >=9,"200", Year(Today())-Year([Hire Date]) >=3,"160", Year(Today())-Year([Hire Date]) =2,"120", Year(Today())-Year([Hire Date]) =1,Month(Today())+1, Year(Today())-Year([Hire Date]) =0, (Month(Today())-Month([Hire Date])) * 10) Formula error -- Bad or missing arguments in function call The types of the arguments or the number of arguments supplied do not meet the requirements of the function If. The function is defined to be If (Boolean condition1, result1, ..., else-result). Re: Need help on a syntax errorSame error. :(Re: Need help on a syntax error That exact formula gives me a syntax error saying that there are extra characters at the end of the function. I tried: IF( year(today())-year([hire date]) >=9,"200", year(today())-year([hire date])>=3,"160", year(today())-year([hire date]) =2,"120", year(today())-year([hire date]) =1,Month(Today())+1, year(today())-year([hire date]) =0, (Month(today())-Month([hire date]) * 10)) and get that there are not enough arguments for an If function, so I tried this: IF( year(today())-year([hire date]) >=9,"200", year(today())-year([hire date])>=3,"160", year(today())-year([hire date]) =2,"120", year(today())-year([hire date]) =1,Month(Today())+1, year(today())-year([hire date]) =0, (Month(today())-Month([hire date]) * 10),0) And I'm still getting Formula error - bad or missing arguments in function call. Need help on a syntax error Hey all, I hope someone can help me. I'm trying to create a numeric formula that will calculate the amount of PTO available to my employees based upon their hire date, but I keep getting a syntax error when I input the formula. Can someone please look at this and see where I am going wrong? Thanks! Case(year(today())-year([hire date]), >=9,"200", >=3,"160", =2,"120", =1,Month(Today())+1, =0,Sum(month(today())-Month([hire date]))*10)