+7Does this function support capturing groups, and if yes, how does one access the captured data?
Intent is to use a this function looking for punctuation from a text field, and then add a new line to this.
regex: ([.!?])\s*
substitution: $1\n
Documentation doesn't state one way or the other. I've tried escaping the new line value without success. Perhaps I'm just missing something simple.
Best answer by Mez
Found the solution: capturing is referred to with backslash 1, which needs to be escaped.
RegexReplace( [Additional Notes], "([.!?])\\s*", "\\1\n" )
+7Posting this again.
Found the solution: capturing is referred to with backslash 1, which needs to be escaped.
RegexReplace( [Additional Notes], "([.!?])\\s*", "\\1\n" )
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