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Question

How to invoke a form from a button click

  • August 15, 2018
  • 0 replies
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Hi Quickbase Community Developers,

I have created a new form on the table. This means that the table now has two forms - the original / default one which I always land on when I invoke the application and the additional one which I just created. All the fields in the new form are also on the default form however the new form has fewer fields than the default form. In the default form I have also created a button that I would like to invoke the new form with when it?s clicked. Do you guys know how can I code the button on the default form to invoke / display the new form when it?s clicked. Kindly advise.

Thanks,

Johannes
    This topic has been closed for replies.

    no problem

    make a URL formula field to switch forms

    URLRoot() & "db/" & dbid() & "?a=dr&dfid=10&rid=" & [Record ID#]

    That is saying to use form ID #10.  The forms are numbered when you view the forms list.

    If you want to edit instead of display, you would change the dr (display record) to er (edit record)

     
    • JohannesMweli
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    • August 16, 2018
    Thank you very much. I am new to Quickbase so it may take me a while to get this to work even though it looks so simple. I will let you know how it goes. 
    • JohannesMweli
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    • Registered
    • August 16, 2018
    Thank you once more, the solution you provided worked fine for me. I am now running into a different problem however that's within the application that I am trying to integrate Quickbase with and i am pretty sure I am going to solve that
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