Forum Discussion
QuickBaseCoachD
9 years agoQrew Captain
The arguments for the Part function are all the delimiter characters you want to trap. So you can do this
Part([Project Name],1," !@#$%^&*';:?/><")
Part([Project Name],1," !@#$%^&*';:?/><")
But, I don't know how to trap a quote ". I will do a quick test now to see if a "" will do it.