Create button to toggle to a secondary form within a table

Question

Please help me with the formula to create a button to toggle to a different form.
Main Form:https://buildproconstructionco.quickbase.com/db/bp5mk38j2?a=dr&r=c&rl=b6qh

2nd Form:https://buildproconstructionco.quickbase.com/db/bp5mk38j2?a=DFormProps&dfid=10&tab=e
thank you

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Lynne8817 Lynne8817
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markshnier__you · Answer

Try thisURLRoot() &amp; "db/" &amp; dbid() &amp; "?a=dr&amp;dfid=10&amp;rid=" &amp; [Record ID#]------------------------------Mark Shnier (YQC)Quick Base Solution ProviderYour Quick Base Coachhttp://QuickBaseCoach.commark.shnier@gmail.com------------------------------

buildpro · Answer

Put this in exactly as you have it written?------------------------------Lynne8817 Lynne8817------------------------------

buildpro · Answer

Worked...how do I "label" the button vs. showing as link?thx------------------------------Lynne8817 Lynne8817------------------------------

markshnier__you · Answer

click the box that says to show as button and enter some Link text.

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Mark Shnier (YQC)
Quick Base Solution Provider
Your Quick Base Coach
http://QuickBaseCoach.com
mark.shnier@gmail.com
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buildpro · Answer

I figured out the label.&nbsp; As always, thank you Mark------------------------------Lynne8817 Lynne8817------------------------------

Forum Discussion

Create button to toggle to a secondary form within a table

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