Can I display a date field as YYYY-MM, where MM would be a two-digit rendering for the month?

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I'd like a field to look at a specific date entered, and then return the year/month in the following format: YYYY-MM, where MM would be two-digit rendering of the month. For example, 1/15/14 would return 2014-01, or 11/2/13 would return 2013-11.

The following formula almost gets me there - except the month shows as a single digit, instead of having a leading 0 when needed.

var number YYYY = Year([SLA Date:]);var number MM = Month([SLA Date:]);(ToText($YYYY)) & "-" & (ToText($MM))
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Posted 6 years ago

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Photo of Mark_Shnier


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No problem, Try this

var text YYYY = Totext(Year([SLA Date:]));

var text MM = right("0" & totext(Month([SLA Date:]),2);

$YYYY & "-" & $MM)

This trick is to zero pad the month, so you stick on a leading zero and then take the rightmost 2 characters.

so, 0 becomes 01 and 12 becomes 012 which gets trimmed to 12 when you take the rightmost 2 characters.
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The "trick is to zero pad the month"! I almost gave up in my search for the answer until I stumbled upon this - thanks Mark!
:) glad my posting from 2 years ago was useful.  I remember the first time someone on this forum showed me how to do that, so I'm just keeping the knowledge alive.
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Minda M

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Yes, this is awesome... I ended up using two of your answers to get what I needed - YYMMDD
Here's what I have:

var date MyDate = ToDate([Date Created]);
var text MM = Right("0" & ToText(Month(ToDate([Date Created]))),2);

var text DD = Right("0" & ToText(Day($MyDate)),2);

var text YY = Right(ToText(Year($MyDate)),2);

$YY & $MM & $DD

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Brian Cafferelli, Quick Base Technical Marketing Manager

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Fun fact: you can use our new PadLeft and PadRight formulas to make sure you have the right number of 0's for your formula. So you could write the formula this way:

var date MyDate = ToDate([Date Created]);
var text MM = PadLeft(ToText(Month(ToDate([Date Created]))),2,"0");

var text DD = PadLeft(ToText(Day($MyDate)),2,"0");

var text YY = PadLeft(ToText(Year($MyDate)),2,"0");

$YY & $MM & $DD

More details in the Formula Functions Reference: