__Field1____Field2__1 3

2 5

3 7

4 2

I need to do 3*5*7*2=210

And I want to show the result as

**Field1**

**Field2**

**Field3**1 3 210

2 5 210

3 7 210

4 2 210

I'm able to figure out the way to make Multiplication possible. Please Help.

- 474 Points

Posted 8 months ago

QuickBaseCoach App Dev./Training, Champion

- 57,308 Points

You will need to create a new table in the app with a single record in it. It will be Record ID 1.

Then make a formula on your details table of 1 and make a relationship.

Then make a sum of a field which multiplied the two numbers.

That is called the “dot product”.

https://en.m.wikipedia.org/wiki/Dot_p...

Then make a formula on your details table of 1 and make a relationship.

Then make a sum of a field which multiplied the two numbers.

That is called the “dot product”.

https://en.m.wikipedia.org/wiki/Dot_p...

(Edited)

Ⲇanom the ultimate (Dan Diebolt), Champion

- 28,904 Points

Follow these steps:

3 * 5 * 7 * 2 = exp( ln(3) + ln(5) + ln(7) + ln(2) )= 210

Then go watch

https://www.amazon.com/Standard-Deviants-Pre-Calculus-Module-Logarithms/dp/B000A2EKTA

- Create a field Ln(
**[Field2]**) in the child table (your existing table) - Summarize this field to the parent field named
**[SumLog]**using addition - Create a formula field in the parent table named
**[Product]**and set it equal to the formula Exp(**[Product]**) - In the child table lookup the field
**[Product]**from the parent

**Law of Logarithms**:3 * 5 * 7 * 2 = exp( ln(3) + ln(5) + ln(7) + ln(2) )= 210

Then go watch

**Standard Deviants**:**Standard Deviants: Pre-Calculus Module 6 - Logarithms**https://www.amazon.com/Standard-Deviants-Pre-Calculus-Module-Logarithms/dp/B000A2EKTA

QuickBaseCoach App Dev./Training, Champion

- 57,308 Points

Thx Dan, I can't imagine when i would need this, but you never know. I tried is on a calculator and it works. I think in a previous life I used to know that.

Ⲇanom the ultimate (Dan Diebolt), Champion

- 28,904 Points

> I tried is on a calculator and it works.

Of course it works - its just simple math.

As a remedial measure I suggest you binge watch a few seasons of

I created a demo

https://haversineconsulting.quickbase.com/db/bnp7nxxq7?a=dr&r=b&rid=1

There are two formulas - one in the child table where

Ln([

and one in the parent table where

Exp(

https://haversineconsulting.quickbase.com/db/bgcwm2m4g?a=dr&rid=655

Of course it works - its just simple math.

As a remedial measure I suggest you binge watch a few seasons of

**Numb3ers**starting with this promo:*He's a mathematician. And He's an FBI agent. And they're both brothers.**https://www.youtube.com/watch?v=EVSFzswY3XY*

I created a demo

**Multiply Child Fields ~ View [Record ID#]= 1**https://haversineconsulting.quickbase.com/db/bnp7nxxq7?a=dr&r=b&rid=1

There are two formulas - one in the child table where

**[Ln]**is calculated as:Ln([

**Number]**)and one in the parent table where

**[Product]**is calculated as:Exp(

**[SumLn]**)**[SumLn]**is a Summary field in**Table #1**and**[Product]**is a lookup table in**Table #2**.**Pastie Database**https://haversineconsulting.quickbase.com/db/bgcwm2m4g?a=dr&rid=655

**Notes:****(1)**you can add your own data to test the application**(2)**you can't enter negative numbers as Ln(x) is not defined for negative numbers.(Edited)

- 474 Points

Vivek Vishwanath

QuickBaseCoach App Dev./Training, Champion

So just make a formula field with a formula of 1 and use that as the reference field in the relationship on he right hand side.

Vivek Vishwanath

And What exactly you are saying when you are saying "formula of 1"?

QuickBaseCoach App Dev./Training, Champion

I think that I misunderstood your question. I now see that you want to be able to multiply data from a field in different rows.

I do not think that there is a way to do that with native Quick Base. Native Quick Base can sum a field using a relationship but not multiply it.

Perhaps if you can explain your use case, I can think of an alternative approach.

Ⲇanom the ultimate (Dan Diebolt), Champion

use logarithms and exponentiation